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Q. When $5$ moles of $He$ gas expand isothermally and reversibly at $300 \,K$ from $10$ litre to $20$ litre, the magnitude of the maximum work obtained is ___$J$. [nearest integer] (Given: $R =8.3\, J \,K ^{-1} \,mol ^{-1}$ and $\log 2=0.3010$ )

JEE MainJEE Main 2022Thermodynamics

Solution:

$n =5 \,mol$
$T =300 \,K$
$V _{1}=10 \,L$
$V _{2}=20\, L$
$w =- nRT \ell n \frac{ V _{2}}{ V _{1}}$
$=-5 \times 8.3 \times 300 \times \ell n \frac{20}{10}$
$=-8630.38 \, J$