Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
When 4 g of iron is burnt to ferric oxide at constant pressure, 29.28 kJ of heat is evolved. What is the enthalpy of formation of ferric oxide? (At. wt. of Fe = 56 )
Q. When
4
g
of iron is burnt to ferric oxide at constant pressure,
29.28
k
J
of heat is evolved. What is the enthalpy of formation of ferric oxide? (At. wt. of
F
e
=
56
)
2495
275
Thermodynamics
Report Error
A
−
40.99
k
J
11%
B
−
81.98
k
J
16%
C
+
818.8
k
J
0%
D
−
819.8
k
J
74%
Solution:
Weight of iron burnt
=
4
g
Heat liberated
=
29.28
k
J
and atomic weight of iron
=
56
In ferric oxide
(
F
e
2
O
3
)
,
2
moles of iron or
2
×
56
=
112
g
of iron are burnt.
Also, when
4
g
of iron are burnt, then heat liberated
=
29.28
k
J
.
when
112
g
of iron are burnt, then heat liberated
=
−
4
29.28
×
112
=
−
819.8
k
J
Therefore, enthalpy of formation of ferric oxide is
−
819.8
k
J
.