When 32.25 g of ethyl chloride is subjected to dehydrohalogenation reaction the yield of the alkene formed is 50% . The mass of the product formed is: (atomic mass of chlorine is 35.5 )

Question

When 32.25 g of ethyl chloride is subjected to dehydrohalogenation reaction the yield of the alkene formed is 50% . The mass of the product formed is: (atomic mass of chlorine is 35.5 ) (A) 14 g (B) 28 g (C) 64.5 g (D) 56 g

Tardigrade Admin · Accepted Answer

C2H5Cl xrightarrow[]dehydroha log enationC2H4 (24+5+35.5) (24+4) g of C2H5Cl forms = 64.5 g of C2H5Cl forms=28 text g text C2H4 ∴ 32.25 text g text of text C2H5Cl will form =(28/64.5)× 32.25 =14 g C2H4.

Q. When $32.25 g$ of ethyl chloride is subjected to dehydrohalogenation reaction the yield of the alkene formed is $50$ . The mass of the product formed is: (atomic mass of chlorine is $35.5$ )

14 g

28 g

64.5 g

56 g

7g

$C_{2} H_{5} Cl d e h y d ro ha l o g e na t i o n C_{2} H_{4}$
$(24 + 5 + 35.5)$ $(24 + 4)$ g of $C_{2} H_{5} Cl$ forms $= 64.5 g o f C_{2} H_{5} Cl f or m s = 28 g C_{2} H_{4}$
$∴$ $32.25 g o f C_{2} H_{5} Cl$ will form $= \frac{28}{64.5} \times 32.25$ $= 14 g C_{2} H_{4} .$

Q. When 32.25g of ethyl chloride is subjected to dehydrohalogenation reaction the yield of the alkene formed is 50 . The mass of the product formed is: (atomic mass of chlorine is 35.5 )