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Q. When $ 32.25 \,g $ of ethyl chloride is subjected to dehydrohalogenation reaction the yield of the alkene formed is $ 50% $ . The mass of the product formed is: (atomic mass of chlorine is $ 35.5 $ )

KEAMKEAM 2005

Solution:

$ {{C}_{2}}{{H}_{5}}Cl\xrightarrow[{}]{dehydroha\log enation}{{C}_{2}}{{H}_{4}} $
$ (24+5+35.5) $ $ (24+4) $ g of $ {{C}_{2}}{{H}_{5}}Cl $ forms $ = 64.5 \,g \,of\, C_2H_5Cl\,forms=28\text{ }g\text{ }{{C}_{2}}{{H}_{4}} $
$ \therefore $ $ 32.25\text{ }g\text{ }of\text{ }{{C}_{2}}{{H}_{5}}Cl $ will form $ =\frac{28}{64.5}\times 32.25 $ $ =14\,g\,{{C}_{2}}{{H}_{4}}. $