When 1 mol CrCl3.6H2O is treated with excess of AgNO3 , 3 mol of AgCl are obtained. The formula of the complex is

Question

When 1 mol CrCl3.6H2O is treated with excess of AgNO3 , 3 mol of AgCl are obtained. The formula of the complex is (A) [(CrCl)3 (H2 O)3].3H2O (B) [(CrCl)2 (H2 O)4]Cl.2H2O (C) [CrCl (H2 O)5](Cl)2⋅ H2O (D) [Cr (H2 O)6](Cl)3

Tardigrade Admin · Accepted Answer

1 mol CrCl3.6H2O is treated with excess of AgNO3 , 3 mol of AgCl are obtained. This indicates that there are three chloride ions present in ionisation sphere. So the formula of complex will be [Cr (H2 O)6](Cl)3 . [Cr (H2 O)6](Cl)3+3(AgNO)3 arrow 3AgCl+[Cr (H2 O)6]3 ++3NO3-

Q. When $1 m o l C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , $3 m o l$ of $A g Cl$ are obtained. The formula of the complex is

$[(C r Cl)_{3} (H_{2} O)_{3}] .3 H_{2} O$

$[(C r Cl)_{2} (H_{2} O)_{4}] Cl .2 H_{2} O$

$[C r Cl (H_{2} O)_{5}] (Cl)_{2} \cdot H_{2} O$

$[C r (H_{2} O)_{6}] (Cl)_{3}$

Q. When 1molCrCl3​.6H2​O is treated with excess of AgNO3​ , 3mol of AgCl are obtained. The formula of the complex is

[(CrCl)3​(H2​O)3​].3H2​O

[(CrCl)2​(H2​O)4​]Cl.2H2​O

[CrCl(H2​O)5​](Cl)2​⋅H2​O

[Cr(H2​O)6​](Cl)3​

Q. When $1 m o l C r C l_{3} .6 H_{2} O$ is treated with excess of $A g N O_{3}$ , $3 m o l$ of $A g Cl$ are obtained. The formula of the complex is

$[(C r Cl)_{3} (H_{2} O)_{3}] .3 H_{2} O$

$[(C r Cl)_{2} (H_{2} O)_{4}] Cl .2 H_{2} O$

$[C r Cl (H_{2} O)_{5}] (Cl)_{2} \cdot H_{2} O$

$[C r (H_{2} O)_{6}] (Cl)_{3}$