When 0.2 mole of anhydrous CuSO4 is dissolved in water, the heat evolved is 1.451 kcal. If 0.2 mole of CuSO4.5H2O is dissolved in water, the heat absorbed is 0.264 kcal. Calculate the molar heat of hydration of CuSO4.

Question

When 0.2 mole of anhydrous CuSO4 is dissolved in water, the heat evolved is 1.451 kcal. If 0.2 mole of CuSO4.5H2O is dissolved in water, the heat absorbed is 0.264 kcal. Calculate the molar heat of hydration of CuSO4. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

CuSO4(s) +H2O → CuSO4(aq) Δ H = (-1.451/0.2) = -7.255 k cal mol-1 (ii) CuSO4. 5H2O(s) + H2O→ CuSO4(aq) Δ H = (0.264/0.2) = 1.32 k cal mol-1 From(i)-(ii), CuSO4(s) +5H2O(1)→ CuSO4.5H2O(s) Δ H =-28.575 k cal mol-1

Q. When 0.2 mole of anhydrous CuSO4​ is dissolved in water, the heat evolved is 1.451 kcal. If 0.2 mole of CuSO4​.5H2​O is dissolved in water, the heat absorbed is 0.264 kcal. Calculate the molar heat of hydration of CuSO4​.

CuSO4​(s)+H2​O→CuSO4​(aq) ΔH=0.2−1.451​=−7.255kcalmol−1 (ii)CuSO4​.5H2​O(s)+H2​O→CuSO4​(aq) ΔH=0.20.264​=1.32kcalmol−1 From(i)-(ii), CuSO4​(s)+5H2​O(1)→CuSO4​.5H2​O(s) ΔH=−28.575kcalmol−1

Q. When $0.2$ mole of anhydrous $C u S O_{4}$ is dissolved in water, the heat evolved is $1.451$ kcal. If $0.2$ mole of $C u S O_{4} .5 H_{2} O$ is dissolved in water, the heat absorbed is $0.264$ kcal. Calculate the molar heat of hydration of $C u S O_{4}$ .