What would be the weight of CO having same number of oxygen atoms as are present in 88gm of CO2:

Question

What would be the weight of CO having same number of oxygen atoms as are present in 88gm of CO2: (A) 112g (B) 56g (C) 28g (D) 168g

Tardigrade Admin · Accepted Answer

Number of oxygen atoms in 88gmCO2 (88/44)× 2× NA⇒ 4NA Oxygen atom 1 Oxygen atom arrow 1CO molecule 4NA oxygen atom arrow 4NACO molecule 4moleCO wCO=mol× Mw =4× 28 =112gm

Q. What would be the weight of $CO$ having same number of oxygen atoms as are present in $88 g m$ of $C O_{2} :$

$112 g$

$56 g$

$28 g$

$168 g$

Number of oxygen atoms in $88 g m C O_{2}$
$\frac{88}{44} \times 2 \times N_{A} \Rightarrow 4 N_{A}$ Oxygen atom
$1$ Oxygen atom $\to 1 CO$ molecule
$4 N_{A}$ oxygen atom $\to 4 N_{A} CO$ molecule
$4 m o l e CO$
$w_{CO} = m o l \times M_{w}$
$= 4 \times 28$
$= 112 g m$

Q. What would be the weight of CO having same number of oxygen atoms as are present in 88gm of CO2​:

112g

56g

28g

168g