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  4. What would be the weight of CO having same number of oxygen atoms as are present in 88gm of CO2:

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Q. What would be the weight of $CO$ having same number of oxygen atoms as are present in $88gm$ of $CO_{2}:$

NTA AbhyasNTA Abhyas 2020

Solution:

Number of oxygen atoms in $88gmCO_{2}$
$\frac{88}{44}\times 2\times N_{A}\Rightarrow 4N_{A}$ Oxygen atom
$1$ Oxygen atom $ \rightarrow 1CO$ molecule
$4N_{A}$ oxygen atom $ \rightarrow 4N_{A}CO$ molecule
$4moleCO$
$w_{CO}=mol\times M_{w}$
$=4\times 28$
$=112gm$