Question

What would be ${\Psi }_0$ of cell sap in cell-$A$ and cell-$B$ respectively?

• A. 300, 400 kPa
• B. -300, -400 kPa
• C. -1100, -1600 kPa
• D. 900, 600 kPa

Answer 1

Answer: (A)

Cell-$A$
${\Psi }_w=-900kPa$
${\Psi }_s=-1200kPa$
${\Psi }_w={\Psi }_s+{\Psi }_p$
${\Psi }_p={\Psi }_w-{\Psi }_s$
$=-900-(-1200)$
$=-900+1200$
${\Psi }_p=+300kPa$
Cell-$B$
${\Psi }_w=-600kPa$
${\Psi }_s=-1000kPa$
${\Psi }_w={\Psi }_s+{\Psi }_p$
$\therefore {\Psi }_p={\Psi }_w-{\Psi }_s$
$=-600-(-1000)$
$=-600+1000)$
${\Psi }_p=400kPa$