What will be the unit of time in that system in which the unit of length is metre, unit of mass is kg and unit of force is kg wt?

Question

What will be the unit of time in that system in which the unit of length is metre, unit of mass is kg and unit of force is kg wt? (A) (9.8)2 s (B) 9.8 s (C) √9.8 s (D) (1/√9.8) s

Tardigrade Admin · Accepted Answer

As [F] = [MLT-2] ∴ T2 = (ML/F) = (1 kg×1 m/1 kg wt) =(1 kg× 1 m/9.8 N) (∵ 1 kg wt = 9.8 N) or = (1/√9.8) s

Q. What will be the unit of time in that system in which the unit of length is metre, unit of mass is kg and unit of force is kg wt?

$(9.8)^{2} s$

$9.8 s$

$9.8 s$

$\frac{1}{9.8} s$

As $[F] = [M L T^{- 2}]$
$∴ T^{2} = \frac{M L}{F} = \frac{1 k g \times 1 m}{1 k g wt} = \frac{1 k g \times 1 m}{9.8 N}$
$(∵ 1 k g wt = 9.8 N)$ or $= \frac{1}{9.8} s$

Q. What will be the unit of time in that system in which the unit of length is metre, unit of mass is kg and unit of force is kg wt?

(9.8)2s

9.8s

9.8​s

9.8​1​s

As [F]=[MLT−2] ∴T2=FML​=1kgwt1kg×1m​=9.8N1kg×1m​ (∵1kgwt=9.8N) or =9.8​1​s

$(9.8)^{2} s$

$9.8 s$

$9.8 s$

$\frac{1}{9.8} s$

As $[F] = [M L T^{- 2}]$
$∴ T^{2} = \frac{M L}{F} = \frac{1 k g \times 1 m}{1 k g wt} = \frac{1 k g \times 1 m}{9.8 N}$
$(∵ 1 k g wt = 9.8 N)$ or $= \frac{1}{9.8} s$