Question

What will be the spin only magnetic moment of high spin and low spin $d^5$ electronic system in an octahedral complex?

• A. ${\mu }_{\text{high spin}}=1.73MB$ and ${\mu }_{\text{low spin}}=5.92BM$
• B. ${\mu }_{\text{high spin}}=5.92BM$ and ${\mu }_{\text{low spin}}=1.73BM$
• C. ${\mu }_{\text{high spin}}=4.9BM$ and ${\mu }_{\text{low spin}}=2.83BM$
• D. ${\mu }_{\text{high spin}}=1.73BM$ and ${\mu }_{\text{low spin}}=1.73BM$

Answer 1

Answer: (B)

High spin $d^5$ system : $t_{2g}^3{e}_g^2$
$t_{2g}^3{e}_g^2$
No. of unpaired electrons $(n)=5$
Magnetic moment, $\mu =\sqrt{n\left(n+2\right)}$ B.M.
${\mu }_{\text{high spin}}=\sqrt{5\left(5+2\right)}$
$=5.92$ B.M.
Low spin $d^5$ system : $t_{2g}^5$
$t_{2g}^5$ : ; $n=1$
${\mu }_{\text{low spin}}=\sqrt{1\left(1+2\right)}$
$=1.73B.M.$