What will be the pH of 0.1 M ammonium acetate solution? (p Ka=p Kb=4.74)

Question

What will be the pH of 0.1 M ammonium acetate solution? (p Ka=p Kb=4.74) (A) 4.74 (B) 6.74 (C) 7.74 (D) 7.00

Tardigrade Admin · Accepted Answer

Ammonium acetate ( CH 3 COONH 4) is a salt of weak acid and weak base. p H=7+(1/2)(p Ka-p Kb) Given that, p Ka=p Kb=4.74 Putting that values, we get p H=7+(1/2)(4.74-4.74)=7+0=7

Q. What will be the $p H$ of $0.1 M$ ammonium acetate solution? $(p K_{a} = p K_{b} = 4.74)$

4.74

6.74

7.74

7.00

Ammonium acetate $(C H_{3} COON H_{4})$ is a salt of weak acid and weak base.
$p H = 7 + \frac{1}{2} (p K_{a} - p K_{b})$
Given that, $p K_{a} = p K_{b} = 4.74$
Putting that values, we get
$p H = 7 + \frac{1}{2} (4.74 - 4.74) = 7 + 0 = 7$

Q. What will be the pH of 0.1M ammonium acetate solution? (pKa​=pKb​=4.74)