Q.
What will be the magnetic field at point P in the figure below?
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NTA AbhyasNTA Abhyas 2020Moving Charges and Magnetism
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Solution:
Field due to section 1 B→1=4πRμ0i upwards
field due to section 2 B2=4πRμ0i(π)=4Rμ0i upwards
Field due to section 3 B→3=4πRμ0i upwards
therefore B→net=B→1+B→2+B→3 upwards B→net=4πRμ0i+4Rμ0i+4πRμ0i upwards Bnet =4Rμ0i(π2+1) upwards