What will be the entropy change of the system when expansion of 1 mole of a gas takes place from 3 L to 6 L under isothermal conditions? Consider, R=2 text cal textK- 1mol- 1 and log 2=0.301.

Question

What will be the entropy change of the system when expansion of 1 mole of a gas takes place from 3 L to 6 L under isothermal conditions? Consider, R=2 text cal textK- 1mol- 1 and log 2=0.301. (A) 2.84 text cal textK- 1 (B) 1.386 text cal textK- 1 (C) 0.37 text cal textK- 1 (D) 5.26 text cal textK- 1

Tardigrade Admin · Accepted Answer

n=1,Vi=3L,Vf=6L Δ S=2.303nRlog10 (Vf/Vi) Δ S=2.303× 1× 2log (6/3)=2.303× 2× 0.3010 =1.386 text cal textK- 1

Q. What will be the entropy change of the system when expansion of 1 mole of a gas takes place from 3 L to 6 L under isothermal conditions? Consider, $R = 2 cal K^{- 1} m o l^{- 1}$ and $l o g 2 = 0.301.$

$2.84 cal K^{- 1}$

$1.386 cal K^{- 1}$

$0.37 cal K^{- 1}$

$5.26 cal K^{- 1}$

$n = 1, V_{i} = 3 L, V_{f} = 6 L$

$Δ S = 2.303 n Rl o g_{10} \frac{V _{f}}{V _{i}}$

$Δ S = 2.303 \times 1 \times 2 l o g \frac{6}{3} = 2.303 \times 2 \times 0.3010$

$= 1.386 cal K^{- 1}$

Q. What will be the entropy change of the system when expansion of 1 mole of a gas takes place from 3 L to 6 L under isothermal conditions? Consider, R=2 cal K−1mol−1 and log2=0.301.

2.84 cal K−1

1.386 cal K−1

0.37 cal K−1

5.26 cal K−1