Question

What will be the difference in $pH$ of $10^{-3}M$ $KOH$ solution and $10^{-5}MKOH$ solution?

Answer 1

Answer: 2

$[O{H}^{-}]=10^{-3}M$
$\therefore pOH=3$
$[O{H}^{-}]=10^{-5}M$
$\therefore pOH=5$
$pH+pOH=14,$
$\therefore pH=14-3=11$
$pH+pOH=14,$
$\therefore pH=14-5=9$
Difference $=11-9=2$