What will be the current flowing through the 6 K Ω resistor in the circuit shown, where the breakdown voltage of the zener is 6 V ?

Question

What will be the current flowing through the 6 K Ω resistor in the circuit shown, where the breakdown voltage of the zener is 6 V ? (A) (3/2) m A  (B) 1 mA (C) 10 mA (D) (3/2) mA

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/fab9601eb8e3f593cd60680e2c302b7a-.png" /> In the given circuit, the zener diode is used as a voltage regulating device. The voltage across 6 k Ω resistance is (10-6) V =4 V Current through 6 kΩ resistor, I=(4 V /6 k Ω)=(4/6 × 103) =(2/3) × 10-3=(2/3) mA

Q. What will be the current flowing through the $6 K Ω$ resistor in the circuit shown, where the breakdown voltage of the zener is $6 V$ ?

$\frac{3}{2} m A$

$1 m A$

$10 m A$

$\frac{3}{2} m A$

In the given circuit, the zener diode is used as a voltage regulating device. The voltage across $6 k Ω$ resistance is $(10 - 6) V = 4 V$
Current through $6 k Ω$ resistor,
$I = \frac{4 V}{6 k Ω} = \frac{4}{6 \times 1 0 ^{3}}$
$= \frac{2}{3} \times 1 0^{- 3} = \frac{2}{3} m A$

Q. What will be the current flowing through the 6KΩ resistor in the circuit shown, where the breakdown voltage of the zener is 6V ?

23​mA

1mA

10mA

23​mA

In the given circuit, the zener diode is used as a voltage regulating device. The voltage across 6kΩ resistance is (10−6)V=4V Current through 6kΩ resistor, I=6kΩ4V​=6×1034​ =32​×10−3=32​mA

Q. What will be the current flowing through the $6 K Ω$ resistor in the circuit shown, where the breakdown voltage of the zener is $6 V$ ?

$\frac{3}{2} m A$

$1 m A$

$10 m A$

$\frac{3}{2} m A$

In the given circuit, the zener diode is used as a voltage regulating device. The voltage across $6 k Ω$ resistance is $(10 - 6) V = 4 V$
Current through $6 k Ω$ resistor,
$I = \frac{4 V}{6 k Ω} = \frac{4}{6 \times 1 0 ^{3}}$
$= \frac{2}{3} \times 1 0^{- 3} = \frac{2}{3} m A$