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Q.
What will be the current flowing through the $6 \,K \Omega$ resistor in the circuit shown, where the breakdown voltage of the zener is $6\, V$ ?
WBJEEWBJEE 2018Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
In the given circuit, the zener diode is used as a voltage regulating device. The voltage across $6 \,k \Omega$ resistance is $(10-6) V =4\, V$
Current through $6\, k\Omega$ resistor,
$I=\frac{4 \,V }{6 \,k \Omega}=\frac{4}{6 \times 10^{3}}$
$=\frac{2}{3} \times 10^{-3}=\frac{2}{3} mA$
