What will be the change in the mass (in grams) of 1 mol benzene if all hydrogen atoms are replaced by tritium atoms? [Atomic masses: Hydrogen =1 u, Tritium =3 u, Carbon =12 u ]

Question

What will be the change in the mass (in grams) of 1 mol benzene if all hydrogen atoms are replaced by tritium atoms? [Atomic masses: Hydrogen =1 u, Tritium =3 u, Carbon =12 u ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Mass of 1 mol of benzene ( C 6 H 6)=78 g If all hydrogen atoms are replaced by tritium atoms, then formula becomes C 6 T 6. Mass of 1 mol of C6 T6=90 g Difference =90-78=12 g

Q. What will be the change in the mass (in grams) of $1 m o l$ benzene if all hydrogen atoms are replaced by tritium atoms?
[Atomic masses: Hydrogen $= 1 u$ , Tritium $= 3 u$ , Carbon $= 12 u$ ]

Mass of $1 m o l$ of benzene $(C_{6} H_{6}) = 78 g$
If all hydrogen atoms are replaced by tritium atoms, then formula becomes $C_{6} T_{6}$ .
Mass of $1 m o l$ of $C_{6} T_{6} = 90 g$
Difference $= 90 - 78 = 12 g$

Q. What will be the change in the mass (in grams) of 1mol benzene if all hydrogen atoms are replaced by tritium atoms? [Atomic masses: Hydrogen =1u, Tritium =3u, Carbon =12u ]

Mass of 1mol of benzene (C6​H6​)=78g If all hydrogen atoms are replaced by tritium atoms, then formula becomes C6​T6​. Mass of 1mol of C6​T6​=90g Difference =90−78=12g

Q. What will be the change in the mass (in grams) of $1 m o l$ benzene if all hydrogen atoms are replaced by tritium atoms?
[Atomic masses: Hydrogen $= 1 u$ , Tritium $= 3 u$ , Carbon $= 12 u$ ]

Mass of $1 m o l$ of benzene $(C_{6} H_{6}) = 78 g$
If all hydrogen atoms are replaced by tritium atoms, then formula becomes $C_{6} T_{6}$ .
Mass of $1 m o l$ of $C_{6} T_{6} = 90 g$
Difference $= 90 - 78 = 12 g$