Question

What will be the bond order of the species with electronic configuration $1s^{2}2s^{2}2p^5$?

• A. One
• B. Two
• C. Three
• D. Zero

Answer 1

Answer: (A)

Electronic configuration of atom: $1s^{2}2s^{2}2p^5$
$M.O.$ configuration
$\left(\sigma 1s^2\right)\left({\sigma }^{\ast }1s^2\right)\left(\sigma 2s^2\right)\left({\sigma }^{\ast }2s^2\right)\left(\sigma 2p_z^2\right)\left(\pi 2p_x^2=\pi 2p_y^2\right)$
$\left({\pi }^{\ast }2p_x^2={\pi }^{\ast }2p_y^2\right)$
$B.O.=\frac{1}{2}\times (10-8)=1$