What will be the angular width of central maxima in Fraunhofer diffraction when the light of wavelength 6000 mathringA is used and slit width is 12× 10- 5cm ?

Question

What will be the angular width of central maxima in Fraunhofer diffraction when the light of wavelength 6000 mathringA is used and slit width is 12× 10- 5cm ? (A) 3rad (B) 8rad (C) 2rad (D) 1rad

Tardigrade Admin · Accepted Answer

ω 0=(2 λ /a) (ω )0=(2 × 6000 × (10)- 10 (. m .)/12 × (10)- 7 (. m .)) ω 0=1rad

Q. What will be the angular width of central maxima in Fraunhofer diffraction when the light of wavelength $6000 \overset{˚}{A}$ is used and slit width is $12 \times 1 0^{- 5} c m$ ?

$3 r a d$

$8 r a d$

$2 r a d$

$1 r a d$

$ω_{0} = \frac{2 λ}{a}$
$(ω)_{0} = \frac{2 \times 6000 \times ( 10 ) ^{- 10} ( m )}{12 \times ( 10 ) ^{- 7} ( m )}$
$ω_{0} = 1 r a d$

Q. What will be the angular width of central maxima in Fraunhofer diffraction when the light of wavelength 6000A˚ is used and slit width is 12×10−5cm ?

3rad

8rad

2rad

1rad