Question

What will be the angular width of central maxima in Fraunhofer diffraction when the light of wavelength $6000\,\mathring{A} $ is used and slit width is $12\times 10^{- 5}cm$ ?

• A. $3rad$
• B. $8rad$
• C. $2rad$
• D. $1rad$

Answer 1

Answer: (D)

$\omega _{0}=\frac{2 \lambda }{a}$
$\left(\omega \right)_{0}=\frac{2 \times 6000 \times \left(10\right)^{- 10} \left(\right. m \left.\right)}{12 \times \left(10\right)^{- 7} \left(\right. m \left.\right)}$
$\omega _{0}=1rad$