What will be ratio of speed in first two seconds to the speed in next 4 s ?

Question

What will be ratio of speed in first two seconds to the speed in next 4 s ? (A)  √2:1  (B)  3:1  (C)  2:1  (D)  1:2

Tardigrade Admin · Accepted Answer

v=( text Distance / text Time taken ) As shown in given figure (v1/v2)=((s0/t1)/(s0)t2)=(s0/t1) × (t2/s0) (v1/v2)=(4/2)=(2/1) Therefore, the ratio of speeds is v1: v2=2: 1

Q. What will be ratio of speed in first two seconds to the speed in next $4 s$ ?

$2 : 1$

$3 : 1$

$2 : 1$

$1 : 2$

$v = \frac{Distance}{Time taken}$
As shown in given figure
$\frac{v _{1}}{v _{2}} = \frac{\frac{s _{0}}{t _{1}}}{\frac{s _{0}}{t _{2}}} = \frac{s _{0}}{t _{1}} \times \frac{t _{2}}{s _{0}}$
$\frac{v _{1}}{v _{2}} = \frac{4}{2} = \frac{2}{1}$
Therefore, the ratio of speeds is
$v_{1} : v_{2} = 2 : 1$

Q. What will be ratio of speed in first two seconds to the speed in next 4s ?

2​:1

3:1

2:1

1:2

v= Time taken Distance ​ As shown in given figure v2​v1​​=t2​s0​​t1​s0​​​=t1​s0​​×s0​t2​​ v2​v1​​=24​=12​ Therefore, the ratio of speeds is v1​:v2​=2:1

Q. What will be ratio of speed in first two seconds to the speed in next $4 s$ ?

$2 : 1$

$3 : 1$

$2 : 1$

$1 : 2$

$v = \frac{Distance}{Time taken}$
As shown in given figure
$\frac{v _{1}}{v _{2}} = \frac{\frac{s _{0}}{t _{1}}}{\frac{s _{0}}{t _{2}}} = \frac{s _{0}}{t _{1}} \times \frac{t _{2}}{s _{0}}$
$\frac{v _{1}}{v _{2}} = \frac{4}{2} = \frac{2}{1}$
Therefore, the ratio of speeds is
$v_{1} : v_{2} = 2 : 1$