Question

What weight of $CaC{O}_3$ must be decomposed to produce the sufficient quantity of carbon dioxide to convert $21.2kg$ of $N{a}_{2}C{O}_3$ completely in to $NaHC{O}_3$. [Atomic mass $Na=23$, $Ca=40$]
$CaC{O}_3\to CaO+C{O}_2$
$N{a}_{2}C{O}_3+C{O}_2+H_{2}O\to 2NaHC{O}_3$

• A. $100kg$
• B. $20kg$
• C. $120kg$
• D. $30kg$

Answer 1

Answer: (B)

$<br/>CaC{O}_3\to CaO+C{O}_2<br/>$
$<br/>100-56\to 44<br/>$
$N{a}_{2}C{O}_3+C{O}_2+H_{2}O\to 2NaHC{O}_3$
$<br/>106+18+44\to 2\times 84<br/>$
Now you have $21.2kg$ so $21200\times \frac{44}{106}$. $=8.8kg$ of $C{O}_2$ needed.
From eq. $188000\times \frac{100}{44}$
$=20kg$ of $CaC{O}_3$ is needed.