What volume of oxygen gas ( O 2) measured at 0° C and 1 atm, is needed to burn completely 1 L of propane gas ( C 3 H 8) measured under the same conditions?

Question

What volume of oxygen gas ( O 2) measured at 0° C and 1 atm, is needed to burn completely 1 L of propane gas ( C 3 H 8) measured under the same conditions? (A) 7 L (B) 6 L (C) 5 L (D) 10 L

Tardigrade Admin · Accepted Answer

underset22.4 LC3H8 + underset5 × 22.4 L50 2 arrow 3CO2 + 4H2O For the combustion of 22.4 L propane, oxygen required = 5 × 22.4 L For the combustion of 1 L of propane oxygen required (5 × 22.4/22.4)L = 5 L

Q. What volume of oxygen gas $(O_{2})$ measured at $0^{\circ} C$ and $1 a t m$ , is needed to burn completely $1 L$ of propane gas $(C_{3} H_{8})$ measured under the same conditions?

7 L

6 L

5 L

10 L

$22.4 L C_{3} H_{8} + 5 \times 22.4 L 5 0_{2} \to 3 C O_{2} + 4 H_{2} O$
For the combustion of $22.4 L$ propane, oxygen required = $5 \times 22.4 L$
For the combustion of $1 L$ of propane oxygen required $\frac{5 \times 22.4}{22.4} L$
$= 5 L$

Q. What volume of oxygen gas (O2​) measured at 0∘C and 1atm, is needed to burn completely 1L of propane gas (C3​H8​) measured under the same conditions?

7 L

6 L

5 L

10 L

22.4LC3​H8​​+5×22.4L502​​→3CO2​+4H2​O For the combustion of 22.4L propane, oxygen required = 5×22.4L For the combustion of 1L of propane oxygen required 22.45×22.4​L =5L

Q. What volume of oxygen gas $(O_{2})$ measured at $0^{\circ} C$ and $1 a t m$ , is needed to burn completely $1 L$ of propane gas $(C_{3} H_{8})$ measured under the same conditions?

$22.4 L C_{3} H_{8} + 5 \times 22.4 L 5 0_{2} \to 3 C O_{2} + 4 H_{2} O$
For the combustion of $22.4 L$ propane, oxygen required = $5 \times 22.4 L$
For the combustion of $1 L$ of propane oxygen required $\frac{5 \times 22.4}{22.4} L$
$= 5 L$