What volume of dioxygen is required for complete combustion of 2 volumes of acetylene gas at NTP?

Question

What volume of dioxygen is required for complete combustion of 2 volumes of acetylene gas at NTP? (A) 2 Volumes (B) 5 Volumes (C) 10 Volumes (D) 4 Volumes

Tardigrade Admin · Accepted Answer

underset2 text vol. C 2 H 2+ underset(5/2) text vol. (5/2) O 2 → underset2 textvol2 CO 2+ H 2 O 1 vol. of C2H2 requires =(5/2) vol. of O2 2 vol. of C2H2 requires =(5/2)× 2 = 5 vol. of O2

Q. What volume of dioxygen is required for complete combustion of $2$ volumes of acetylene gas at $NTP$ ?

$2$ Volumes

$5$ Volumes

$10$ Volumes

$4$ Volumes

$2 vol. C_{2} H_{2} + \frac{5}{2} vol. \frac{5}{2} O_{2} \to 2 vol 2 C O_{2} + H_{2} O$
$1$ vol. of $C_{2} H_{2}$ requires = $\frac{5}{2}$ vol. of $O_{2}$
$2$ vol. of $C_{2} H_{2}$ requires = $\frac{5}{2} \times 2 = 5$ vol. of $O_{2}$

Q. What volume of dioxygen is required for complete combustion of 2 volumes of acetylene gas at NTP?

2 Volumes

5 Volumes

10 Volumes

4 Volumes