Question

What is the weight of oxygen that is required the complete combustion of $2.8kg$ of ethylene?

• A. 9.6 kg
• B. 96.0 kg
• C. 6.4 kg
• D. 2.8 kg

Answer 1

Answer: (A)

$\underset{12\times 2+4=28}{C_2{H}_4}+\underset{96}{3O_2}⟶2C{O}_2+2H_{2}O$
$\because$ The weight of oxygen required for complete combustion of $28g$ ethylene $=96g$.
$\therefore$ Weight of oxygen required for combustion of $2.8kg$ ethylene
$=\frac{96\times 2.8\times 1000}{28\times 1000}kg=9.8kg$