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Q.
What is the weight of oxygen that is required the complete combustion of $2.8 \,kg$ of ethylene?
Bihar CECEBihar CECE 2006Some Basic Concepts of Chemistry
Solution:
$\underset{12 \times 2 + 4 = 28}{C _{2} H _{4}}+ \underset{96}{3 O _{2}} \longrightarrow 2 CO _{2}+2 H _{2} O$
$\because$ The weight of oxygen required for complete combustion of $28\, g$ ethylene $=96\, g$.
$\therefore $ Weight of oxygen required for combustion of $2.8\, kg$ ethylene
$=\frac{96 \times 2.8 \times 1000}{28 \times 1000} kg =9.8 \,kg$