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Question
Chemistry
What is the value of n in the following half equation on balancing ? Cr(OH)-4 + OH- arrow CrO2-4 + H2O + ne-
Q. What is the value of n in the following half equation on balancing ?
C
r
(
O
H
)
4
−
+
O
H
−
→
C
r
O
4
2
−
+
H
2
O
+
n
e
−
2212
212
Redox Reactions
Report Error
A
3
47%
B
6
25%
C
5
16%
D
2
11%
Solution:
C
r
(
O
H
)
4
−
+
O
H
(
−
)
⟶
C
r
O
4
2
−
+
H
2
O
+
n
e
(
−
)
Reduction
→
3
H
2
+
1
O
2
−
1
+
6
e
(
−
)
+
6
H
2
O
⟶
6
+
1
H
2
−
2
O
+
6
O
H
(
−
)
So, Value of
n
=
6