What is the total number of moles of H2SO4 needed to prepare 5.0 L of a 2.0 M solution of H2SO4 ?

Question

What is the total number of moles of H2SO4 needed to prepare 5.0 L of a 2.0 M solution of H2SO4 ? (A) 2.5 (B) 5.0 (C) 10 (D) 20

Tardigrade Admin · Accepted Answer

Molarity of a solution is the amount of moles per litre of solution. Hence, Number of moles = Molarity × Volume (in L ) ⇒ Number of moles of H 2 SO 4=2.0 M × 5.0 L =10 moles

Q. What is the total number of moles of $H_{2} S O_{4}$ needed to prepare $5.0 L$ of a $2.0 M$ solution of $H_{2} S O_{4}$ ?

2.5

5.0

10

20

Molarity of a solution is the amount of moles per litre of solution.

Hence,

Number of moles $=$ Molarity $\times$ Volume (in $L$ )

$\Rightarrow$ Number of moles of $H_{2} S O_{4} = 2.0 M \times 5.0 L$

$= 10$ moles

Q. What is the total number of moles of H2​SO4​ needed to prepare 5.0L of a 2.0M solution of H2​SO4​ ?

2.5

5.0

10

20

Molarity of a solution is the amount of moles per litre of solution. Hence, Number of moles = Molarity × Volume (in L ) ⇒ Number of moles of H2​SO4​=2.0M×5.0L =10 moles

Q. What is the total number of moles of $H_{2} S O_{4}$ needed to prepare $5.0 L$ of a $2.0 M$ solution of $H_{2} S O_{4}$ ?

Molarity of a solution is the amount of moles per litre of solution.

Hence,

Number of moles $=$ Molarity $\times$ Volume (in $L$ )

$\Rightarrow$ Number of moles of $H_{2} S O_{4} = 2.0 M \times 5.0 L$

$= 10$ moles