What is the time period of the seconds pendulum, on a planet similar to earth, but mass and radius three times as that of the earth?

Question

What is the time period of the seconds pendulum, on a planet similar to earth, but mass and radius three times as that of the earth? (A) 2 s (B) 6 s (C) (2/√3 )s (D) 2√3 s

Tardigrade Admin · Accepted Answer

g=(G M/R2) (gp/ge)=(Mp/Me)× ((Re/Rp))2=3× (1/9)=(1/3) T=2π √(l/g) (Tp/Te)=√(ge/gp)=√3 Tp=√3Te Time period at earth for seconds pendulum =2 s ∴ Tp=2√3 s

Q. What is the time period of the seconds pendulum, on a planet similar to earth, but mass and radius three times as that of the earth?

$2 s$

$6 s$

$\frac{2}{3} s$

$23 s$

Q. What is the time period of the seconds pendulum, on a planet similar to earth, but mass and radius three times as that of the earth?

2s

6s

3​2​s

23​s

g=R2GM​ ge​gp​​=Me​Mp​​×(Rp​Re​​)2=3×91​=31​ T=2πgl​​ Te​Tp​​=gp​ge​​​=3​ Tp​=3​Te​ Time period at earth for seconds pendulum =2s ∴Tp​=23​s

$2 s$

$6 s$

$\frac{2}{3} s$

$23 s$