What is the shape of the IBr2- ion?

Question

What is the shape of the IBr2- ion? (A) Linear (B) Bent shape with bond angle of about 90°  (C) Bent shape with bond angle of about 109°  (D) Bent shape with bond angle of about 120°

Tardigrade Admin · Accepted Answer

the shape of the IBr2- ion is Linaer <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-ist08zkx0m9k2woe.jpg" /> IBr:X=2+(1/2)[.7 -bonds + 3 lone pairs) texts textp3 textd -hybridisation shape arrow Linear.

Q. What is the shape of the $I B r_{2}^{-}$ ion?

Linear

Bent shape with bond angle of about $9 0^{\circ}$

Bent shape with bond angle of about $10 9^{\circ}$

Bent shape with bond angle of about $12 0^{\circ}$

the shape of the $I B r_{2}^{-}$ ion is Linaer

$I B r : X = 2 + \frac{1}{2} [7$ -bonds + 3 lone pairs) $s p^{3} d$ -hybridisation shape $\to$ Linear.

Q. What is the shape of the IBr2−​ ion?

Linear

Bent shape with bond angle of about 90∘

Bent shape with bond angle of about 109∘

Bent shape with bond angle of about 120∘

the shape of the IBr2−​ ion is Linaer IBr:X=2+21​[7 -bonds + 3 lone pairs) sp3d -hybridisation shape → Linear.

Q. What is the shape of the $I B r_{2}^{-}$ ion?

Bent shape with bond angle of about $9 0^{\circ}$

Bent shape with bond angle of about $10 9^{\circ}$

Bent shape with bond angle of about $12 0^{\circ}$

the shape of the $I B r_{2}^{-}$ ion is Linaer

$I B r : X = 2 + \frac{1}{2} [7$ -bonds + 3 lone pairs) $s p^{3} d$ -hybridisation shape $\to$ Linear.