What is the pH of a solution obtained by mixing 10 mL of 0.1 M HCl and 40 mL of 0.2 M H2SO4

Question

What is the pH of a solution obtained by mixing 10 mL of 0.1 M HCl and 40 mL of 0.2 M H2SO4 (A) 0.74 (B) 7.4 (C) 4.68 (D) 0.468

Tardigrade Admin · Accepted Answer

Millimoles of H+ from HCl = 0.1× 10=1 Millimoles of H+ from H2SO4 = 0.2 × 40 × 2 = 16 Conc, of H+=( textMillimoles/ textVolume)=(16+1/40+10) =(17/50)=0.34 pH=-log [H+] =-log (0.34)=0.468

Q. What is the $p H$ of a solution obtained by mixing $10 m L$ of $0.1 M H Cl$ and $40 m L$ of $0.2 M H_{2} S O_{4}$

$0.74$

$7.4$

$4.68$

$0.468$

Millimoles of $H^{+}$ from $H Cl = 0.1 \times 10 = 1$
Millimoles of $H^{+}$ from $H_{2} S O_{4} = 0.2 \times 40 \times 2 = 16$
Conc, of $H^{+} = \frac{Millimoles}{Volume} = \frac{16 + 1}{40 + 10}$
$= \frac{17}{50} = 0.34$
$p H = - l o g [H^{+}]$
$= - l o g (0.34) = 0.468$

Q. What is the pH of a solution obtained by mixing 10mL of 0.1MHCl and 40mL of 0.2MH2​SO4​

0.74

7.4

4.68

0.468