What is the period of the function sin 4x + tan 2x?

Question

What is the period of the function sin 4x + tan 2x? (A) 2 π  (B) π (C) (π/2) (D) (3 π/2)

Tardigrade Admin · Accepted Answer

Period of sin x is 2 π so, period of sin 4x = (2 π/4) = (π/2) and period of tan x is π, so period of tan 2x = (π/2) So, period of ( sin 4x + tan 2x) = LCM of (π/2) , (π/2) = (π/2)

Q. What is the period of the function sin 4x + tan 2x?

$2 π$

$π$

$\frac{π}{2}$

$\frac{3 π}{2}$

Period of sin x is $2 π$ so, period of
$sin 4 x = \frac{2 π}{4} = \frac{π}{2}$
and period of tan x is $π$ , so period of
$tan 2 x = \frac{π}{2}$
So, period of $(sin 4 x + tan 2 x)$ = LCM of
$\frac{π}{2}, \frac{π}{2} = \frac{π}{2}$

Q. What is the period of the function sin 4x + tan 2x?

2π

π

2π​

23π​

Period of sin x is 2π so, period of sin4x=42π​=2π​ and period of tan x is π, so period of tan2x=2π​ So, period of (sin4x+tan2x) = LCM of 2π​,2π​=2π​

$2 π$

$π$

$\frac{π}{2}$

$\frac{3 π}{2}$

Period of sin x is $2 π$ so, period of
$sin 4 x = \frac{2 π}{4} = \frac{π}{2}$
and period of tan x is $π$ , so period of
$tan 2 x = \frac{π}{2}$
So, period of $(sin 4 x + tan 2 x)$ = LCM of
$\frac{π}{2}, \frac{π}{2} = \frac{π}{2}$