Question

What is the oxidation number of vanadium in $R{b}_{4}Na\left[H{V}_{10}{O}_{28}\right]?$

• A. 8
• B. 5
• C. 3
• D. 1

Answer 1

Answer: (B)

$R{b}_{4}Na\left[H{V}_{10}{O}_{28}\right]$
Let oxidation number of $V$ is $x$.
$\therefore 4\times 1+1+[+1+10x+28(-2)]=0$
or $4+1+1+10x-56=0$
or $x=+5$