What is the mole ratio of benzene ( P B 0=150. torr ) and toluene ( P T 0=50. torr ) in vapour phase if the given solution has a vapour pressure of 120 torr?

Question

What is the mole ratio of benzene ( P B 0=150. torr ) and toluene ( P T 0=50. torr ) in vapour phase if the given solution has a vapour pressure of 120 torr? (A) 7: 1 (B) 7: 3 (C) 8: 1 (D) 7: 8

Tardigrade Admin · Accepted Answer

P=PB0 xB+PT0 xT 120=150(xB)+50(1-xB) 100 xB=70 xB=0.7 YB=(XB PB0/P) (0.7 × 150/120)=0.075 (YB/YT)=(7/1) YT=1-0.875=0.125

Q. What is the mole ratio of benzene $(P_{B}^{0} = 150$ torr $)$ and toluene $(P_{T}^{0} = 50$ torr $)$ in vapour phase if the given solution has a vapour pressure of $120$ torr?

7: 1

7: 3

8: 1

7: 8

$P = P_{B}^{0} x_{B} + P_{T}^{0} x_{T}$

$120 = 150 (x_{B}) + 50 (1 - x_{B})$

$100 x_{B} = 70$

$x_{B} = 0.7$

$Y_{B} = \frac{X _{B} P _{B}^{0}}{P} \frac{0.7 \times 150}{120} = 0.075 \frac{Y _{B}}{Y _{T}} = \frac{7}{1}$

$Y_{T} = 1 - 0.875 = 0.125$

Q. What is the mole ratio of benzene (PB0​=150 torr ) and toluene (PT0​=50 torr ) in vapour phase if the given solution has a vapour pressure of 120 torr?