Question

What is the molarity of $H_{2}S{O}_4$ solution that has a density of $1.84g/cc$ at $35^{\circ }C$ and contains $98\%$ by weight?

• A. 4.18 M
• B. 8.14 M
• C. 18.4 M
• D. 18 M

Answer 1

Answer: (C)

Molarity

$=\frac{\text{ wt. of solute }}{\text{ mol. wt. }}\times \frac{1000}{\text{ vol. of solution (in ml.) }}$

(Volume of solution $=\frac{\text{ mass }}{\text{ density }}=\frac{100}{1.84}$

$=54.34ml$ )

Now molarity $=\frac{98}{98}\times \frac{1000}{54.34}$

$=18.4M$