What is the melting point of benzene if Δ Hf u s i o n=9.95 kJ/mol and Δ Sf u s i o n35.7 J/K-mol?

Question

What is the melting point of benzene if Δ Hf u s i o n=9.95 kJ/mol and Δ Sf u s i o n35.7 J/K-mol? (A) 278.7 texto textC (B) 278.7 K (C) 300 K (D) 298 K

Tardigrade Admin · Accepted Answer

T=(Δ H/Δ S)=(9.95 × 1000/35.7) = 278.7 textK

Q. What is the melting point of benzene if $Δ H_{f u s i o n} = 9.95$ kJ/mol and $Δ S_{f u s i o n} 35.7$ J/K-mol?

$278. 7^{o} C$

278.7 K

300 K

298 K

$T = \frac{Δ H}{Δ S} = \frac{9.95 \times 1000}{35.7}$

$= 278.7 K$

Q. What is the melting point of benzene if ΔHfusion​=9.95 kJ/mol and ΔSfusion​35.7 J/K-mol?

278.7oC

278.7 K

300 K

298 K

T=ΔSΔH​=35.79.95×1000​ =278.7K

Q. What is the melting point of benzene if $Δ H_{f u s i o n} = 9.95$ kJ/mol and $Δ S_{f u s i o n} 35.7$ J/K-mol?

$278. 7^{o} C$

$T = \frac{Δ H}{Δ S} = \frac{9.95 \times 1000}{35.7}$

$= 278.7 K$