What is the mass ratio of ethylene glycol ( C 2 H 6 O 2., molar mass .=62 g / mol ) required for making 500 g of 0.25 molal aqueous solution and 250 mL of 0.25 molal aqueous solution?

Question

What is the mass ratio of ethylene glycol ( C 2 H 6 O 2., molar mass .=62 g / mol ) required for making 500 g of 0.25 molal aqueous solution and 250 mL of 0.25 molal aqueous solution? (A) 1: 2 (B) 1: 1 (C) 3:1 (D) 2:1

Tardigrade Admin · Accepted Answer

Assume: Mass of solvent ≈ Mass of solution Case I :- 0.25=(W1/62) × (1000/500) Case II :- 0.25=( W 2/62) × (1000/250) ( W 1/ W 2)=(2/1)

Q. What is the mass ratio of ethylene glycol $(C_{2} H_{6} O_{2}$ , molar mass $= 62 g / m o l)$ required for making $500 g$ of $0.25$ molal aqueous solution and $250 m L$ of $0.25$ molal aqueous solution?

$1 : 2$

$1 : 1$

$3 : 1$

$2 : 1$

Assume : Mass of solvent $\approx$ Mass of solution
Case I :-
$0.25 = \frac{W _{1}}{62} \times \frac{1000}{500}$
Case II :-
$0.25 = \frac{W _{2}}{62} \times \frac{1000}{250}$
$\frac{W _{1}}{W _{2}} = \frac{2}{1}$

Q. What is the mass ratio of ethylene glycol (C2​H6​O2​, molar mass =62g/mol) required for making 500g of 0.25 molal aqueous solution and 250mL of 0.25 molal aqueous solution?

1:2

1:1

3:1

2:1