Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
What is the mass of urea required for making 2.5 kg of 0.25 molal aqueous solution?
Q. What is the mass of urea required for making
2.5
k
g
of
0.25
molal aqueous solution?
10146
171
Solutions
Report Error
A
37
g
31%
B
25
g
29%
C
125
g
20%
D
27.5
g
20%
Solution:
No. of moles of urea
=
0.25
moles
Mass of solvent
=
1
k
g
=
1000
g
Molar mass of urea
=
60
g
m
o
l
−
1
Mass of urea in
1000
g
of
H
2
O
=
0.25
×
60
=
15
g
Total mass of solution
=
1000
+
15
=
1015
g
1.015
k
g
solution contains
15
g
urea
2.5
k
g
solution will contain
=
1.015
15
×
2.5
=
37
g