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  4. What is the equation of the line which passes through (4, - 5) and is parallel to the line 3x + 4y + 5 = 0 ?

Q. What is the equation of the line which passes through (4, - 5) and is parallel to the line 3x + 4y + 5 = 0 ?

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Solution:

Equation of a line parallel to line 3x + 4y + 5 = 0 is given by 3x + 4y + c = 0 ...(1)
Since, point (4, -5) lies on this line
We have, 3 (4) + 4 (-5) + c = 0, 12 - 20 + c = 0, c = 8