What is the equation form of Langmuir adsorption isotherm under high pressure?

Question

What is the equation form of Langmuir adsorption isotherm under high pressure? (A)  (x/m)=(a/b)  (B)  (x/m)=ap  (C)  (x/m)=(1/ap)  (D)  (x/m)=(b/a)

Tardigrade Admin · Accepted Answer

Langmuir adsorption isotherm is represented as (x/m)=(a p/1+b p) where, a and b are Langmuir parameters. If pressure p is very high then b p>>1, hence 1+b p ≈ b p ∴ (x/m)=(a p/b p)=(a/b)= constant

Q. What is the equation form of Langmuir adsorption isotherm under high pressure?

$\frac{x}{m} = \frac{a}{b}$

$\frac{x}{m} = a p$

$\frac{x}{m} = \frac{1}{a p}$

$\frac{x}{m} = \frac{b}{a}$

Langmuir adsorption isotherm is represented as
$\frac{x}{m} = \frac{a p}{1 + b p}$
where,
$a$ and $b$ are Langmuir parameters.
If pressure $p$ is very high then $b p >> 1$ ,
hence $1 + b p \approx b p$
$∴ \frac{x}{m} = \frac{a p}{b p} = \frac{a}{b} =$ constant

Q. What is the equation form of Langmuir adsorption isotherm under high pressure?

mx​=ba​

mx​=ap

mx​=ap1​

mx​=ab​

Langmuir adsorption isotherm is represented as mx​=1+bpap​ where, a and b are Langmuir parameters. If pressure p is very high then bp>>1, hence 1+bp≈bp ∴mx​=bpap​=ba​= constant

$\frac{x}{m} = \frac{a}{b}$

$\frac{x}{m} = a p$

$\frac{x}{m} = \frac{1}{a p}$

$\frac{x}{m} = \frac{b}{a}$

Langmuir adsorption isotherm is represented as
$\frac{x}{m} = \frac{a p}{1 + b p}$
where,
$a$ and $b$ are Langmuir parameters.
If pressure $p$ is very high then $b p >> 1$ ,
hence $1 + b p \approx b p$
$∴ \frac{x}{m} = \frac{a p}{b p} = \frac{a}{b} =$ constant