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Chemistry
What is the enthalpy of hydrogenation of ethylene, given that the enthalpy of combustion of ethylene, hydrogen and ethane are -1410.0,-286.2 and -1560.6 k J mol-1 respectively at 298 K ?
Q. What is the enthalpy of hydrogenation of ethylene, given that the enthalpy of combustion of ethylene, hydrogen and ethane are
−
1410.0
,
−
286.2
and
−
1560.6
k
J
m
o
l
−
1
respectively at
298
K
?
2328
226
Uttarkhand PMT
Uttarkhand PMT 2010
Report Error
A
135.6
B
-135.6
C
125.6
D
$-125.6
Solution:
Given, (i)
C
2
H
4
(
g
)
+
3
O
2
(
g
)
→
2
C
O
2
(
g
)
+
2
H
2
O
(
l
)
Δ
H
=
−
1410
k
J
m
o
l
−
1
(ii)
H
2
(
g
)
+
2
1
O
2
(
g
)
→
H
2
O
(
l
)
;
Δ
H
=
−
286.2
k
J
m
o
l
−
1
(iii)
C
2
H
6
(
g
)
+
3
2
1
O
2
(
g
)
→
2
C
O
2
(
g
)
+
3
H
2
O
(
l
)
Δ
H
=
−
1560.6
k
J
m
o
l
−
1
Required reaction is
C
2
H
4
+
H
2
(
g
)
→
C
6
H
6
(
g
)
,
Δ
H
=
?
Equation (i) + Equation (ii) - Equation (iii) gives
C
2
H
4
+
H
2
(
g
)
→
C
2
H
6
(
g
)
,
Δ
H
=
−
1410.0
+
(
−
286.2
)
−
(
−
1560.6
)
=
−
135.6
k
J
m
o
l
−
1