What is the enthalpy change accompanying the conversion of graphite into diamond ? Heats of combustion of C text (graphite) and C text (diamond) are -94.05 and -94.50 kcal respectively

Question

What is the enthalpy change accompanying the conversion of graphite into diamond ? Heats of combustion of C text (graphite) and C text (diamond) are -94.05 and -94.50 kcal respectively (A) -188.55 kcal (B) zero (C) 0.45 kcal (D) -94.05 kcal

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/e69b0c7fae1a5240f831efd722e7109b-.png" /> Δ H text reaction=-94.05-(-94.50)=+0.45 kcal

Q. What is the enthalpy change accompanying the conversion of graphite into diamond ? Heats of combustion of $C_{(graphite)}$ and $C_{(diamond)}$ are $- 94.05$ and $- 94.50 k c a l$ respectively

$- 188.55 k c a l$

zero

$0.45 k c a l$

$- 94.05 k c a l$

$Δ H_{reaction} = - 94.05 - (- 94.50) = + 0.45$ kcal

Q. What is the enthalpy change accompanying the conversion of graphite into diamond ? Heats of combustion of C(graphite)​ and C(diamond)​ are −94.05 and −94.50kcal respectively

−188.55kcal

zero

0.45kcal

−94.05kcal

ΔHreaction​=−94.05−(−94.50)=+0.45 kcal

Q. What is the enthalpy change accompanying the conversion of graphite into diamond ? Heats of combustion of $C_{(graphite)}$ and $C_{(diamond)}$ are $- 94.05$ and $- 94.50 k c a l$ respectively

$- 188.55 k c a l$

$0.45 k c a l$

$- 94.05 k c a l$

$Δ H_{reaction} = - 94.05 - (- 94.50) = + 0.45$ kcal