Question

What is the electronic configuration of $M{n}^{2+}$ ?

• A. [Ne] $3d^5,4s^0$
• B. $[Ar]3d^5,4s^2$
• C. $[Ar]3d^5,4s^0$
• D. [Ne] $3d^5,4s^2$

Answer 1

Answer: (C)

Electronic configuration of $Mn(25)$ is
$\therefore 1s^2,2s^2,2p^6,3s^2,3p^6,4s^2,3d^5$
Electronic configuration of $M{n}^{2+}$ is
$1s^2,2s^2,2p^6,3s^2,3p^6,3d^5$
$\because M{n}^{2+}=[Ar]3d^5,4s^0$