What is the electrode potential of Fe3+/ Fe electrode in which concentration of Fe3+ ions is 0.1 M. Given E° Fe3+/Fe = + 0.771 V

Question

What is the electrode potential of Fe3+/ Fe electrode in which concentration of Fe3+ ions is 0.1 M. Given E° Fe3+/Fe = + 0.771 V (A) +0.79 V (B) +0.75 V (C) 1.50 V (D) + 1.0 V

Tardigrade Admin · Accepted Answer

Fe3+ + 3e- arrow Fe E = E0 - (0.059/n) log ([Fe]/[Fe3+]) = + 0.771 - (0.059/n) log (1/0.1) = + 0.75 V

Q. What is the electrode potential of $F e^{3 +} / F e$ electrode in which concentration of $F e^{3 +}$ ions is $0.1 M$ . Given $E^{\circ} F e^{3 +} / F e = + 0.771 V$

+0.79 V

+0.75 V

1.50 V

+ 1.0 V

$F e^{3 +} + 3 e^{-} \to F e$
$E = E^{0} - \frac{0.059}{n} l o g \frac{[ F e ]}{[ F e ^{3 +} ]}$
$= + 0.771 - \frac{0.059}{n} l o g \frac{1}{0.1}$
$= + 0.75 V$

Q. What is the electrode potential of Fe3+/Fe electrode in which concentration of Fe3+ ions is0.1M. Given E∘Fe3+/Fe=+0.771V