What is the distance between nearest neighbours and next nearest neighbours if potassium crystallises in BCC lattice with edge length =5 mathringA ?

Question

What is the distance between nearest neighbours and next nearest neighbours if potassium crystallises in BCC lattice with edge length =5 mathringA ? (A) 4.33 mathringA, 5 mathringA (B) 5 mathringA, 2 mathringA (C) 6 mathringA, 8.5 mathringA (D) 8 mathringA, 3.5 mathringA

Tardigrade Admin · Accepted Answer

Nearest neighbours distance in BCC =(√3 a /2)=(√3/2) × 5 =4.33 mathringA Next nearest neighbour distance = a =5 mathringA

Q. What is the distance between nearest neighbours and next nearest neighbours if potassium crystallises in BCC lattice with edge length $= 5 \overset{˚}{A}$ ?

$4.33 \overset{˚}{A}, 5 \overset{˚}{A}$

$5 \overset{˚}{A}, 2 \overset{˚}{A}$

$6 \overset{˚}{A}, 8.5 \overset{˚}{A}$

$8 \overset{˚}{A}, 3.5 \overset{˚}{A}$

Nearest neighbours distance in $BCC = \frac{3 a}{2} = \frac{3}{2} \times 5$

$= 4.33 \overset{˚}{A}$

Next nearest neighbour distance $= a = 5 \overset{˚}{A}$

Q. What is the distance between nearest neighbours and next nearest neighbours if potassium crystallises in BCC lattice with edge length =5A˚ ?

4.33A˚,5A˚

5A˚,2A˚

6A˚,8.5A˚

8A˚,3.5A˚