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  4. What is the distance between nearest neighbours and next nearest neighbours if potassium crystallises in BCC lattice with edge length =5 mathringA ?

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Q. What is the distance between nearest neighbours and next nearest neighbours if potassium crystallises in BCC lattice with edge length $=5 \mathring{A}$ ?

The Solid State

Solution:

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Nearest neighbours distance in $BCC =\frac{\sqrt{3} a }{2}=\frac{\sqrt{3}}{2} \times 5$

$=4.33 \mathring{A}$

Next nearest neighbour distance $= a =5\mathring{A}$

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