What is the dimensional formula of dynamic viscosity?

Question

What is the dimensional formula of dynamic viscosity? (A) [M1 L1 T-2] (B) [M1 L1 T-1] (C) [ M 1 L -1 T -1] (D) [M1 L1 T1]

Tardigrade Admin · Accepted Answer

Dynamic viscosity μ=τ ⋅ (d y/d ϵ). τ= shearing stress (d y/⋅ d ϵ) = velocity gradient m =[ M 1 L 1 T 2][ T 1]=[ M 1 L 1 T 1] same as that of coefficient of viscosity.

Q. What is the dimensional formula of dynamic viscosity?

$[M^{1} L^{1} T^{- 2}]$

$[M^{1} L^{1} T^{- 1}]$

$[M^{1} L^{- 1} T^{- 1}]$

$[M^{1} L^{1} T^{1}]$

Dynamic viscosity $μ = τ \cdot \frac{d y}{d ϵ}$ .
$τ =$ shearing stress
$\frac{d y}{\cdot d ϵ}$ = velocity gradient
$m = [M^{1} L^{1} T^{2}] [T^{1}] = [M^{1} L^{1} T^{1}]$
same as that of coefficient of viscosity.

Q. What is the dimensional formula of dynamic viscosity?

[M1L1T−2]

[M1L1T−1]

[M1L−1T−1]

[M1L1T1]

Dynamic viscosity μ=τ⋅dϵdy​. τ= shearing stress ⋅dϵdy​ = velocity gradient m=[M1L1T2][T1]=[M1L1T1] same as that of coefficient of viscosity.

$[M^{1} L^{1} T^{- 2}]$

$[M^{1} L^{1} T^{- 1}]$

$[M^{1} L^{- 1} T^{- 1}]$

$[M^{1} L^{1} T^{1}]$

Dynamic viscosity $μ = τ \cdot \frac{d y}{d ϵ}$ .
$τ =$ shearing stress
$\frac{d y}{\cdot d ϵ}$ = velocity gradient
$m = [M^{1} L^{1} T^{2}] [T^{1}] = [M^{1} L^{1} T^{1}]$
same as that of coefficient of viscosity.