Question

What is the dimensional formula of dynamic viscosity?

• A. $\left[M^{1} L^{1} T^{-2}\right]$
• B. $\left[M^{1} L^{1} T^{-1}\right]$
• C. $\left[ M ^{1} L ^{-1} T ^{-1}\right]$
• D. $\left[M^{1} L^{1} T^{1}\right]$

Answer 1

Answer: (C)

Dynamic viscosity $\mu=\tau \cdot \frac{d y}{d \epsilon}$.
$\tau=$ shearing stress
$\frac{d y}{\cdot d \epsilon}$ = velocity gradient
$m =\left[ M ^{1} L ^{1} T ^{2}\right]\left[ T ^{1}\right]=\left[ M ^{1} L ^{1} T ^{1}\right]$
same as that of coefficient of viscosity.