What is the decreasing order of strength of the bases? OH-, NH2-,H-C≡ C- and CH3-CH2- ?

Question

What is the decreasing order of strength of the bases? OH-, NH2-,H-C≡ C- and CH3-CH2- ? (A) CH3-CH2->NH2->H-C≡ C->OH- (B) H-C≡ C->CH3-CH2->NH2->OH- (C) OH->NH2->H-C≡ C->CH3-CH2- (D) NH2->H-C≡ C->OH->CH3-CH2-

Tardigrade Admin · Accepted Answer

As the strength of conjugate base α 1/acidic strength As acidic strength is textHOH> textHC≡ textCH> textN textH3> textC textH3- textC textH3 So textC textH3- textC textH2-> textN textH2->H-C≡ C-> textO textH-

Q. What is the decreasing order of strength of the bases?
$O H^{-}, N H_{2}^{-}, H - C \equiv C^{-}$ and $C H_{3} - C H_{2}^{-}$ ?

$C H_{3} - C H_{2}^{-} > N H_{2}^{-} > H - C \equiv C^{-} > O H^{-}$

$H - C \equiv C^{-} > C H_{3} - C H_{2}^{-} > N H_{2}^{-} > O H^{-}$

$O H^{-} > N H_{2}^{-} > H - C \equiv C^{-} > C H_{3} - C H_{2}^{-}$

$N H_{2}^{-} > H - C \equiv C^{-} > O H^{-} > C H_{3} - C H_{2}^{-}$

As the strength of conjugate base $α$ 1/acidic strength
As acidic strength is
$HOH > HC \equiv CH > N H_{3} > C H_{3} - C H_{3}$
So $C H_{3} - C H_{2}^{-} > N H_{2}^{-} > H - C \equiv C^{-} > O H^{-}$

Q. What is the decreasing order of strength of the bases? OH−,NH2−​,H−C≡C− and CH3​−CH2−​ ?

CH3​−CH2−​>NH2−​>H−C≡C−>OH−

H−C≡C−>CH3​−CH2−​>NH2−​>OH−

OH−>NH2−​>H−C≡C−>CH3​−CH2−​

NH2−​>H−C≡C−>OH−>CH3​−CH2−​